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Post by Chele on Feb 24, 2006 16:37:16 GMT -5
Bring it on guys! I'll have it out around 11 on Saturday. Okay...I think I'll be there too...and I let Debbie know, so she might show too! ;D |
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Post by vabeachtj on Feb 24, 2006 19:00:44 GMT -5
Just keep welding Dave, oh yeah, don't forget surf camp for the neighborhood kids too! I'll be looking to see the plans for the teeter totter tomorrow. ;D Ok, I think my neighbors are starting to get nervous now! 3 Jeeps, a big Ramcharger, Billy's F250, my heep and EB, and Craig (what was that you drove?) all out front with everyone checking out a big ramp-looking thing in the garage. A neighbor even came by to find out what it is we're building and then came back with something to get welded! Hey as long as they don't complain- Fine-tuning cuts-  Tacking-  More tacking-  Tapping in a shim-  Ok, so we took a break-  Now it's coming together-   Should be useable this week but I need more steel for side braces, preferably 2"x3" or 2"x4". Pics by Michele(Chele) |
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Post by CORE 4WD on Feb 25, 2006 1:04:01 GMT -5
awesome, so you're sort of near harpers rd as well? i just got a job at a machine shop that way. might explain why I saw you at a traffic light the other day! I thought that was you! I was trying to catch up. Which shop? |
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Post by CORE 4WD on Feb 25, 2006 1:07:53 GMT -5
Dave, I'm sorry I forgot to check on if that thing is going to needs lights, registration, etc. I'll check today. But just looking at its size, I think it's going to be considered a trailer, and you'll have to put lights on it, get a homemade trailer application and VIN plate from DMV and register it. Who's gonna pay for all that? And personal property taxes! It might be easier and cheaper just to haul it on someone else's trailer! Anyway, I can sign the homemade trailer inspection easy enough, then it can be registered. About how long is it, and what's it weigh? It's about 13 feet, probably less than 500 lbs...Thanks for any info, I don't mind paying fees if it keeps 5.O off my back! Oh yea that's u!! |
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Post by Chele on Feb 25, 2006 14:00:44 GMT -5
Thanks Dave for fixing my junk!  |
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Post by CORE 4WD on Feb 25, 2006 21:16:39 GMT -5
Had fun this afternoon on the ramp, was able to troubleshoot a couple of things. Here's some more shots. Jay you still have the furthest distance!- Thanks Billy and Jim for the late nighter finishing up trim- Tapping bolt holes-   Matt (ILOVEMYYJ)   Michelle (CHELE) Dig those new fenders!   Debbie (VABEACHTJ)  Two sweet Rubicons. No competition here! Michelle left Deb right-   |
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Post by Jim63 on Feb 25, 2006 23:04:47 GMT -5
ok so who's in the lead now? And Dave let me know when you plan on haveing some more late night fun!!!
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Post by Jim63 on Feb 25, 2006 23:06:22 GMT -5
my bad I just read that jay is still in the lead! haha
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Post by What It Was on Feb 25, 2006 23:11:16 GMT -5
That's a big-a$$ ramp, GOOD WORK BRO!!!.... What is the length and height of it?...
Man, I gotta get my project done!!!! BECAUSE.... I have to run my rig to the top of it hahaha, Imagine that.
Anyway, I was curious to figure the actual angle using Trig with the height and length to figure the actual angle that's why I asked...
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Post by CORE 4WD on Feb 26, 2006 7:57:07 GMT -5
That's a big-a$$ ramp, GOOD WORK BRO!!!.... What is the length and height of it?... Man, I gotta get my project done!!!! BECAUSE.... I have to run my rig to the top of it hahaha, Imagine that. Anyway, I was curious to figure the actual angle using Trig with the height and length to figure the actual angle that's why I asked... It's 132' long and 61' high... |
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Post by Chele on Feb 26, 2006 8:48:56 GMT -5
Oh and Dave...that RTI calculator I sent you the link for uses the vertical disatance from the top to the ground. Don't worry, I did cos(23) x 66 and got it!! (I think 66 was my score!) That would make the distance from 66" on the ramp to the ground 35" Well, I think I got it, I may need to go downstairs and check my trig book to make sure I used the right forumla!
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Post by What It Was on Feb 26, 2006 15:05:59 GMT -5
Alright this is what I got... I used Contangent A/0= 132/61= 2.1639 I looked at my Natural trig funcion book and it gave 2.1642 being the closest... only off by .0003... which gives a total angle of 24 degrees and 48 minutes....
The length of the Hypotenuse is 145.411"= 12'118 (rounded) so your overall dimesnions are 5'083" tall.... 11' long.... and the length of the Hypontenuse is 12'1175"... with an angle of 24 degrees and 48 minutes (Providing measurements are what they were said to be).
I double checked the angle using cosecant... and it vareifed 24 degrees and 48 minutes of angle. all the math adds up with the dimensions given... Hopefully this will help....
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Post by Chele on Feb 26, 2006 16:09:16 GMT -5
I always enjoy a good math challenge. I used sin x = opposite side (b=61) divided by the hypotenuse (c=132) or sin x = 61/132 To find the angle of the ramp, which is x: Sin x=61/132 Sin x=0.462121212121 x= appox 27.5 degrees Fife: If you used cotangent, that is adjacent side divided by opposite, which means you would have to solve for the missing side which is 117 inches. So, Cot x= 117/61 Cot x=1.91 x = 27.5 degrees I think you meant to use cosecent which is hypotenuse over opposite side or simply the inverse sin function. I used this trig table to figure this out: www.math2.org/math/trig/tables.htm |
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Post by What It Was on Feb 26, 2006 17:48:27 GMT -5
In Basic Right Angle Trig you have to have two givens to find another... ie: 2 outsides to find and inside... one in one out to find or solve for "x" etc etc... So, If I take the Length (132") which will be my ADJACENT.... and then I take my height (61") which is my OPPOSITE and I'm solving for X... "X" being the desired angle... So... COTANGENT=A/O which = 132/61= 2.16393. Now if you have a TRIGONOMETRY TABLE BOOK (REFERENCE)... You will then look under the COTANGENT COLUMN until you find 2.16393... You then look over at the side and it'll tell you the Degrees and minutes... which equal 24 degrees and 48 minutes...
Now, with that angle being known.. we can solve for "X" So, I use SECANT=H/A which gives me X/132... seeing that I have a given angle (24 degrees 48 Minutes) I look under SECANT in my TRIONOMETRY TABLE REFERENCE at 24 degrees and 48 minutes and the number that it shows is 1.1016... I take that number and multiply it by 132 which = 145.4112 now to figure in feet divide by 12 which equals 12.1176... which is just over 12' 7/64" and just under 12' 1/8".
These formulas aren't wrong.. if you'd like I'll show all math on paper with TRIGONOMETRY TABLES ETC...
But, I'm with you... I like a good math problem... Double check your math and add up all the angles and see if you get 180. I did 3 times now using different formula fucntions and I keep getting the same answers... The way I did it is "A lot" more accurate...
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Post by What It Was on Feb 26, 2006 17:51:32 GMT -5
Oh yeah... I forgot to mention Chele that In RIGHT ANGLE TRIG the HYPOTENUSE will Always be the longest side... No-matter what. That's one quick way you can check.
We use these formulas when cutting something REALLY REALLY IMPORTANT FOR SUBS ETC ETC... We use these formulas to cut the basic stuff on a VTL (Verticle Turret Lathe)... We even use them on the conventional lathes to figure the proper angles and reliefs.
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